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Q31. - (Topic 2) 

Refer to the exhibit. 

Assume that all of the router interfaces are operational and configured correctly. How will router R2 be affected by the configuration of R1 that is shown in the exhibit? 

A. Router R2 will not form a neighbor relationship with R1. 

B. Router R2 will obtain a full routing table, including a default route, from R1. 

C. R2 will obtain OSPF updates from R1, but will not obtain a default route from R1. 

D. R2 will not have a route for the directly connected serial network, but all other directly connected networks will be present, as well as the two Ethernet networks connected to R1. 

Answer:

Explanation: 

Open Shortest Path First http://en.wikipedia.org/wiki/Open_Shortest_Path_First 

The configuration of R1 shows "router ospf 1" however, the diagram also shows that both routers should be in the backbone OSPF Area of "0". When routers are in different OSPF areas they will not form a neighbor relationship. Neighbor relationships As a link state routing protocol, OSPF establishes and maintains neighbor relationships in order to exchange routing updates with other routers. The neighbor relationship table is called an adjacency database in OSPF. Provided that OSPF is configured correctly, OSPF forms neighbor relationships only with the routers directly connected to it. In order to form a neighbor relationship between two routers, the interfaces used to form the relationship must be in the same area. Generally an interface is only configured in a single area, however you can configure an interface to belong to multiple areas. In the second area, such an interface must be configured as a secondary interface. (A neighbor state simulation shows how neighbor state changes from Down to Full Adjacency progressively with exchanging Hello, DD, Request, Update, and Ack packets). 


Q32. - (Topic 3) 

Which command is used to enable CHAP authentication, with PAP as the fallback method, on a serial interface? 

A. Router(config-if)# ppp authentication chap fallback ppp 

B. Router(config-if)# ppp authentication chap pap 

C. Router(config-if)# authentication ppp chap fallback ppp 

D. Router(config-if)# authentication ppp chap pap 

Answer:

Explanation: 

The command “ppp authentication chap pap” command indicates the CHAP authentication is used first. If it fails or is rejected by other side then uses PAP instead. If you want to use PAP first (then CHAP) you can use the “ppp authentication pap chap” command 

Reference: http://www.cisco.com/en/US/docs/ios/12_2/security/configuration/guide/scfathen.html 


Q33. - (Topic 2) 

What information does a router running a link-state protocol use to build and maintain its topological database? (Choose two.) 

A. hello packets 

B. SAP messages sent by other routers 

C. LSAs from other routers 

D. beacons received on point-to-point links 

E. routing tables received from other link-state routers 

F. TTL packets from designated routers 

Answer: A,C 

Explanation: 

Link State Routing Protocols http://www.ciscopress.com/articles/article.asp?p=24090&seqNum=4 

Link state protocols, sometimes called shortest path first or distributed database protocols, are built around a well-known algorithm from graph theory, E. W. Dijkstra'a shortest path algorithm. Examples of link state routing protocols are: Open Shortest Path First (OSPF) for IP The ISO's Intermediate System to Intermediate System (IS-IS) for CLNS and IP DEC's DNA Phase V Novell's NetWare Link Services Protocol (NLSP) Although link state protocols are rightly considered more complex than distance vector protocols, the basic functionality is not complex at all: 

1. Each router establishes a relationship—an adjacency—with each of its neighbors. 

2. Each router sends link state advertisements (LSAs), some 

3. Each router stores a copy of all the LSAs it has seen in a database. If all works well, the databases in all routers should be identical. 

4. The completed topological database, also called the link state database, describes a graph of the internetwork. Using the Dijkstra algorithm, each router calculates the shortest path to each network and enters this information into the route table. 


Q34. - (Topic 2) 

Refer to the exhibit. 

C-router is to be used as a "router-on-a-stick" to route between the VLANs. All the interfaces have been properly configured and IP routing is operational. The hosts in the VLANs have been configured with the appropriate default gateway. What is true about this configuration? 

A. These commands need to be added to the configuration: C-router(config)# router eigrp 123 C-router(config-router)# network 172.19.0.0 

B. These commands need to be added to the configuration: C-router(config)# router ospf 1 C-router(config-router)# network 172.19.0.0 0.0.3.255 area 0 

C. These commands need to be added to the configuration: C-router(config)# router rip C-router(config-router)# network 172.19.0.0 

D. No further routing configuration is required. 

Answer:

Explanation: 

http://www.cisco.com/en/US/tech/tk389/tk815/technologies_configuration_example09186a 00800949fd.shtml https://learningnetwork.cisco.com/servlet/JiveServlet/download/5669-2461/Router%20on%20a%20Stick.pdf. 


Q35. - (Topic 2) 

What are two benefits of using a single OSPF area network design? (Choose two.) 

A. It is less CPU intensive for routers in the single area. 

B. It reduces the types of LSAs that are generated. 

C. It removes the need for virtual links. 

D. It increases LSA response times. 

E. It reduces the number of required OSPF neighbor adjacencies. 

Answer: B,C 

Explanation: 

OSPF uses a LSDB (link state database) and fills this with LSAs (link state advertisement). The link types are as follows: 

LSA Type 1:. Router LSA  

LSA Type 2:.. . . . . . . .  Network LSA  

LSA Type 3:. Summary LSA  

LSA Type 4:. Summary ASBR LSA  

LSA Type 5:. Autonomous system external LSA  

LSA Type 6:. Multicast OSPF LSA  

LSA Type 7:. Not-so-stubby area LSA  

LSA Type 8:. External attribute LSA for BGP  

If all routers are in the same area, then many of these LSA types (Summary ASBR LSA, external LSA, etc) will not be used and will not be generated by any router. 

All areas in an Open Shortest Path First (OSPF) autonomous system must be physically connected to the backbone area (Area 0). In some cases, where this is not possible, you can use a virtual link to connect to the backbone through a non-backbone area. You can also use virtual links to connect two parts of a partitioned backbone through a non-backbone area. The area through which you configure the virtual link, known as a transit area, must have full routing information. The transit area cannot be a stub area. Virtual links are not ideal and should really only be used for temporary network solutions or migrations. However, if all locations are in a single OSPF area this is not needed. 


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Q36. - (Topic 2) 

Refer to the exhibit. 

The Lakeside Company has the internetwork in the exhibit. The administrator would like to reduce the size of the routing table on the Central router. Which partial routing table entry in the Central router represents a route summary that represents the LANs in Phoenix but no additional subnets? 

A. 10.0.0.0/22 is subnetted, 1 subnets D 10.0.0.0 [90/20514560] via 10.2.0.2, 6w0d, Serial0/1 

B. 10.0.0.0/28 is subnetted, 1 subnets D 10.2.0.0 [90/20514560] via 10.2.0.2, 6w0d, Serial0/1 

C. 10.0.0.0/30 is subnetted, 1 subnets D 10.2.2.0 [90/20514560] via 10.2.0.2, 6w0d, Serial0/1 

D. 10.0.0.0/22 is subnetted, 1 subnets D 10.4.0.0 [90/20514560] via 10.2.0.2, 6w0d, Serial0/1 

E. 10.0.0.0/28 is subnetted, 1 subnets D 10.4.4.0 [90/20514560] via 10.2.0.2, 6w0d, Serial0/1 

F. 10.0.0.0/30 is subnetted, 1 subnets D 10.4.4.4 [90/20514560] via 10.2.0.2, 6w0d, Serial0/1 

Answer:

Explanation: 

All the above networks can be summarized to 10.0.0.0 network but the question requires to “represent the LANs in Phoenix but no additional subnets” so we must summarized to 

10.4.0.0 network. The Phoenix router has 4 subnets so we need to “move left” 2 bits of “/24-> /22 is the best choice - D is correct. 


Q37. - (Topic 2) 

Refer to the exhibit. 

When running EIGRP, what is required for RouterA to exchange routing updates with RouterC? 

A. AS numbers must be changed to match on all the routers 

B. Loopback interfaces must be configured so a DR is elected 

C. The no auto-summary command is needed on Router A and Router C 

D. Router B needs to have two network statements, one for each connected network 

Answer: A Explanation: 

Here we required same autonomous system between router A,B,C.Routing updated always exchange between in same EIGRP EIGRP autonomous system.you can configure more than one EIGRP autonomous system on the same router. This is typically done at a redistribution point where two EIGRP autonomous systems are interconnected. Individual router interfaces should only be included within a single EIGRP autonomous system. Cisco does not recommend running multiple EIGRP autonomous systems on the same set of interfaces on the router. If multiple EIGRP autonomous systems are used with multiple points of mutual redistribution, it can cause discrepancies in the EIGRP topology table if correct filtering is not performed at the redistribution points. If possible, Cisco recommends you configure only one EIGRP autonomous system in any single autonomous system. http://www.cisco.com/en/US/tech/tk365/technologies_tech_note09186a0080093f07.shtml 


Q38. - (Topic 2) 

Which statement describes an EIGRP feasible successor route? 

A. A primary route, added to the routing table 

B. A backup route, added to the routing table 

C. A primary route, added to the topology table 

D. A backup route, added to the topology table 

Answer:

Explanation: 

Two terms that appear often in the EIGRP world are "successor" and "feasible successor". A successor is the route with the best metric to reach a destination. That route is stored in the routing table. A feasible successor is a backup path to reach that same destination that can be used immediately if the successor route fails. These backup routes are stored in the topology table. 

Reference: http://study-ccna.com/eigrp-overview 


Q39. - (Topic 2) 

Refer to the exhibit. 

Given the output from the “show ip eigrp topology” command, which router is the feasible successor? 

A) 

B) 

C) 

D) 

A. Exhibit A 

B. Exhibit B 

C. Exhibit C 

D. Exhibit D 

Answer:

Explanation: 

To be the feasible successor, the Advertised Distance (AD) of that route must be less than the Feasible Distance (FD) of the successor. From the output of the “show ip eigrp topology 

10.0.0.5 255.255.255.255 we learn that the FD of the successor is 41152000. Now we will mention about the answers, in the “Composite metric is (…/…)” statement the first parameter is the FD while the second parameter is the AD of that route. So we need to find out which route has the second parameter (AD) less than 41152000 -> only answer B satisfies this requirement with an AD of 128256. 

Reference: http://networklessons.com/eigrp/eigrp-neighbor-and-topology-table-explained/ 


Q40. - (Topic 2) 

Which two are advantages of static routing when compared to dynamic routing? (Choose two.) 

A. Configuration complexity decreases as network size increases. 

B. Security increases because only the network administrator may change the routing table. 

C. Route summarization is computed automatically by the router. 

D. Routing tables adapt automatically to topology changes. 

E. An efficient algorithm is used to build routing tables, using automatic updates. 

F. Routing updates are automatically sent to neighbors. 

G. Routing traffic load is reduced when used in stub network links. 

Answer: B,G 

Explanation: 

When reading (or being lectured about) all the glorious details of dynamic routing protocols, it's hard not to come away with the impression that dynamic routing is always better than static routing. It's important to keep in mind that the primary duty of a dynamic routing protocol is to automatically detect and adapt to topological changes in the internetwork. The price of this "automation" is paid in bandwidth, security, and maybe queue space, in memory, and in processing time. A frequent objection to static routing is that it is hard to administer. This criticism may be true of medium to large topologies with many alternative routes, but it is certainly not true of small internetworks with few or no alternative routes. References: http://www.ciscopress.com/articles/article.asp?p=24090&seqNum=6 http://www.ciscopress.com/articles/article.asp?p=24090